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0.220x^2-15x-135=0
a = 0.220; b = -15; c = -135;
Δ = b2-4ac
Δ = -152-4·0.220·(-135)
Δ = 343.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{343.8}}{2*0.220}=\frac{15-\sqrt{343.8}}{0.44} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{343.8}}{2*0.220}=\frac{15+\sqrt{343.8}}{0.44} $
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